3n^2-25=30

Solution for 3n^2-25=30 equation:

3n^2-25=30

We move all terms to the left:

3n^2-25-(30)=0

We add all the numbers together, and all the variables

3n^2-55=0

a = 3; b = 0; c = -55;
Δ = b2-4ac
Δ = 02-4·3·(-55)
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{165}}{2*3}=\frac{0-2\sqrt{165}}{6}
=-\frac{2\sqrt{165}}{6}
=-\frac{\sqrt{165}}{3}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{165}}{2*3}=\frac{0+2\sqrt{165}}{6}
=\frac{2\sqrt{165}}{6}
=\frac{\sqrt{165}}{3}
$